Problem 1: Multiples of 3 and 5
c# :
int i = 1000;
int sum = 0;
for (int j = 3; j < i; j++)
{
if (j % 3 == 0 || j % 5 == 0)
sum = sum + j;
}
Console.Write(sum);
Console.ReadLine();
---
Problem is pretty straight forward,
just loop through the numbers less than 1000 (started from 3 to save two loops :) )
if either 3 or 5 divides the number evenly, add it to the sum.
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
int i = 1000;
int sum = 0;
for (int j = 3; j < i; j++)
{
if (j % 3 == 0 || j % 5 == 0)
sum = sum + j;
}
Console.Write(sum);
Console.ReadLine();
---
Problem is pretty straight forward,
just loop through the numbers less than 1000 (started from 3 to save two loops :) )
if either 3 or 5 divides the number evenly, add it to the sum.
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